By G. H. Ryder, M. D. Bennett (auth.)

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**Extra info for Mechanics of Machines**

**Example text**

2, how far up the ladder mayan 80 kg man climb before slip occurs? 15 m] 11. 25. What downward force P on the end of the layer is just sufficient to stop the wheel turning under the applied anticlockwise moment M? The coefficient of friction between the brake block and the wheel is J1.. Show on the free-body diagram what happens if J1. = ale. What effect does the direction of rotation have on the answers? [M[al J1. 25 12. A uniform rod tests perpendicularly and symmetrically across two parallel rails, the coefficient of friction being the same at both points of contact.

The foot of the ladder rests on horizontal ground. 2, how far up the ladder mayan 80 kg man climb before slip occurs? 15 m] 11. 25. What downward force P on the end of the layer is just sufficient to stop the wheel turning under the applied anticlockwise moment M? The coefficient of friction between the brake block and the wheel is J1.. Show on the free-body diagram what happens if J1. = ale. What effect does the direction of rotation have on the answers? [M[al J1. 25 12. A uniform rod tests perpendicularly and symmetrically across two parallel rails, the coefficient of friction being the same at both points of contact.

Find also the total distance travelled in the 4 seconds. 1 v = dx / dt = 10 - 6t 42 MECHANICS OF MACHINES therefore f: f: dx= (1O-6t)dt x=[lOt-3t2]~= -8 m From inspection of the given data it is clear that the particle has an initial velocity of to mis, which decreases to zero and then becomes negative. After 4 seconds the particle has returned to its starting point and moved a further 8 m in the opposite direction to which it started. 3. (10 x i)+! 67 m (a) Motion Under Constant Acceleration In the previous example, the acceleration is a constant.